CRT-450 FREE BRAIN DUMPS - 100% PASS QUIZ FIRST-GRADE SALESFORCE CRT-450 - SALESFORCE CERTIFIED PLATFORM DEVELOPER I EXAMINATIONS ACTUAL QUESTIONS

CRT-450 Free Brain Dumps - 100% Pass Quiz First-grade Salesforce CRT-450 - Salesforce Certified Platform Developer I Examinations Actual Questions

CRT-450 Free Brain Dumps - 100% Pass Quiz First-grade Salesforce CRT-450 - Salesforce Certified Platform Developer I Examinations Actual Questions

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Salesforce CRT-450 (Salesforce Certified Platform Developer I) Certification Exam is a globally recognized certification exam that validates the skills and knowledge of developers in building custom applications on the Salesforce platform. CRT-450 exam is designed to assess the skills required to develop and deploy custom business logic and interfaces using Apex and Visualforce, and to manage data and metadata on the Salesforce platform. Salesforce Certified Platform Developer I certification is aimed at developers who have experience with the Salesforce platform, programming concepts and object-oriented programming languages such as Java, C#, and C++.

Salesforce CRT-450 Exam is a valuable certification for individuals who want to start their career as a Salesforce platform developer. Salesforce Certified Platform Developer I certification is a foundation-level certification that assesses the essential knowledge and skills required to develop custom applications on the Salesforce platform. Passing the Salesforce CRT-450 exam demonstrates a candidate's proficiency in Salesforce development and validates their expertise in developing custom applications using Apex and Visualforce.

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Salesforce Certified Platform Developer I Sample Questions (Q198-Q203):

NEW QUESTION # 198
Which two statement can a developer use to throw a custom exception of type MissingFieldValueException?Choose 2 answers

  • A. Throw new MissingFieldValueException('Problem occurred');
  • B. Throw Exception(new MissingFieldValueException());
  • C. Throw (MissingFieldValueException,'Problem occurred');
  • D. Throw new MissingFieldValueException();

Answer: A,D


NEW QUESTION # 199
What are two use cases for executing Anonymous Apex code? Choose 2 answers

  • A. To delete 15,000 inactive Accounts In a single transaction after a deployment
  • B. To schedule an Apex class to run periodically
  • C. To add unit test code coverage to an org
  • D. To run a batch Apex class to update all Contacts

Answer: B,D


NEW QUESTION # 200
A developer has a Apex controller for a Visualforce page that takes an ID as a URL parameter. How should the developer prevent a cross site scripting vulnerability?

  • A. String.escapeSingleQuotes(ApexPages.currentPage() .getParameters(). get('url_param'))
  • B. ApexPages.currentPage() .getParameters() .get('url_param')
  • C. ApexPages.currentPage() .getParameters() .get('url_param') .escapeHtml4()
  • D. String.ValueOf(ApexPages.currentPage() .getParameters() .get('url_param'))

Answer: D

Explanation:
Cross site scripting (XSS) is a vulnerability that occurs when an attacker can insert unauthorized HTML or JavaScript code into a web page viewed by other users. This can lead to hijacking the user's session, stealing confidential information, or defacing the page. To prevent XSS, the developer should always validate and encode any user-supplied data before displaying it on the page. The ApexPages.currentPage() .getParameters()
.get('url_param') method returns the value of the URL parameter as a string, but does not perform any validation or encoding. Therefore, it is vulnerable to XSS if the parameter contains malicious code. The ApexPages.currentPage() .getParameters() .get('url_param') .escapeHtml4() method escapes the HTML characters in the parameter value, such as <, >, &, and ", but does not prevent JavaScript code from being executed. Therefore, it is also vulnerable to XSS if the parameter contains a script tag or an event handler attribute. The String.escapeSingleQuotes(ApexPages.currentPage() .getParameters(). get('url_param')) method escapes the single quotes in the parameter value, but does not affect any other characters. Therefore, it is also vulnerable to XSS if the parameter contains any HTML or JavaScript code. The String.ValueOf(ApexPages.currentPage() .getParameters() .get('url_param')) method converts the parameter value to a string and encodes any HTML characters as HTML entities, such as <, >, &, and ". This prevents any HTML or JavaScript code from being rendered or executed on the page. Therefore, it is the best option to prevent XSS. References: You can learn more about XSS and how to prevent it in Apex from the following sources:
* Cross Site Scripting (XSS) | Apex Developer Guide
* Secure Coding Cross Site Scripting | Secure Coding Guide
* Cross-Site Scripting in Apex | SecureFlag Security Knowledge Base


NEW QUESTION # 201
A developer is creating a page that allows users to create multiple Opportunities. The developer is asked to verify the current user's default Opportunity record type, and set certain default values based on the record type before inserting the record.
How can the developer find the current user's default record type?

  • A. Query the Profile where the ID equals uzexInfo.getProfilelD () and then use the profile.Cpportunity.gesDefaultRecordTyp= () method.
  • B. Create the opportunity and check the opportunity. recordTyp=, which will have the record ID of the current user's default record type, before inserting.
  • C. Use the Schema.userInfo.Cpportunity.getlefaultRecordIype () method.
  • D. Use Opportunity.SObjectType.gethescribe () .getRaecordlypaInsos () to get a list of record types, and iterate through them until 2sDefaultRecordTypeMapping () is true.

Answer: D

Explanation:
To find the current user's default record type for Opportunity, the developer can use the DescribeSObjectResult and RecordTypeInfo classes.
Option A: Use Opportunity.SObjectType.getDescribe().getRecordTypeInfos() to get a list of record types, and iterate through them until isDefaultRecordTypeMapping() is true.
Correct Approach.
// Get describe result for Opportunity
Schema.DescribeSObjectResult oppDescribe = Opportunity.SObjectType.getDescribe();
// Get list of RecordTypeInfo
List<Schema.RecordTypeInfo> recordTypeInfos = oppDescribe.getRecordTypeInfos();
// Iterate through RecordTypeInfo to find the default one
Id defaultRecordTypeId;
for (Schema.RecordTypeInfo rtInfo : recordTypeInfos) {
if (rtInfo.isAvailable() && rtInfo.isDefaultRecordTypeMapping()) {
defaultRecordTypeId = rtInfo.getRecordTypeId();
break;
}
}
Reference:
Options Not Applicable:
Option B and C: Methods mentioned do not exist in the API.
Option D: Create the Opportunity and check the Opportunity.RecordTypeId before inserting.
The RecordTypeId is not automatically populated before inserting.
Conclusion:
To find the current user's default Opportunity record type, the developer should use Option A.


NEW QUESTION # 202
A developer created an Apex trigger using the Developer Console and now wants to debug codeHow can the developer accomplish this in the Developer Console?

  • A. Open the logs tab in the Developer Console.
  • B. Add the user name in the Log Inspector.
  • C. Select the Override Log Triggers checkbox for the trigger
  • D. Open the Progress tab in the Developer Console.

Answer: A


NEW QUESTION # 203
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